How can I package or install an entire program to run in an AWS Lambda function

If this is a case of using Lambda entirely the wrong way, please let me know.

I want to install Scrapy into a Lambda function and invoke the function to begin a crawl. My first problem is how to install it, so that all of the paths are correct. I installed the program using the directory to be zipped as its root, so the zip contains all of the source files and the executable. I am basing my efforts on this article. In the line it says to include at the beginning of my function, where does the "process" variable come from? I have tried,

var process = require('child_process');
var exec = process.exec;
process.env['PATH'] = process.env['PATH'] + ':' + 
process.env['LAMBDA_TASK_ROOT']

but I get the error,

"errorMessage": "Cannot read property 'PATH' of undefined",
"errorType": "TypeError",

Do I need to include all of the library files, or just the executable from /usr/lib ? How do I include that one line of code the article says I need?

Edit: I tried moving the code into a child_process.exec, and received the error

"errorMessage": "Command failed: /bin/sh: process.env[PATH]: command not found\n/bin/sh: scrapy: command not found\n"

Here is my current, entire function

console.log("STARTING");
var process = require('child_process');
var exec = process.exec;

exports.handler = function(event, context) {    
    //Run a fixed Python command.
    exec("process.env['PATH'] = process.env['PATH'] + ':' + process.env['LAMBDA_TASK_ROOT']; scrapy crawl backpage2", function(error, stdout) {
        console.log('Scrapy returned: ' + stdout + '.');
        context.done(error, stdout);
    });

};